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Find total number of customers with a purchase history
7 years 7 months ago #304322
by simplecms
Find total number of customers with a purchase history was created by simplecms
-- HikaShop version -- : 3.5.1
Is there a way to show a report of ALL TIME customers who have made a purchase? Not orders, but customers who have made orders?
Is there a way to show a report of ALL TIME customers who have made a purchase? Not orders, but customers who have made orders?
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7 years 7 months ago #304365
by nicolas
Replied by nicolas on topic Find total number of customers with a purchase history
Hi,
There are ways.
First, if you use a mass action on the orders with an action "display the results" and select the user columns you want, you'll get the customers information who placed an order. However, you'll get doublons as you'll get the customer information once for each of their orders. If you instead use the "export CSV file" action and open the CSV in excel, you can easily filter the CSV to remove duplicates: support.office.com/en-us/article/filter-...9b-bbe1-8daaec1e83c2
Second, you can use the report system on the user data and select the "best customers" option and increase the number of results.
That will give you a listing of the customers sorted from most important number of purchases to worst.
There are ways.
First, if you use a mass action on the orders with an action "display the results" and select the user columns you want, you'll get the customers information who placed an order. However, you'll get doublons as you'll get the customer information once for each of their orders. If you instead use the "export CSV file" action and open the CSV in excel, you can easily filter the CSV to remove duplicates: support.office.com/en-us/article/filter-...9b-bbe1-8daaec1e83c2
Second, you can use the report system on the user data and select the "best customers" option and increase the number of results.
That will give you a listing of the customers sorted from most important number of purchases to worst.
Please Log in or Create an account to join the conversation.
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