Just did it again. Here you go
Error
SQL query:
-- phpMyAdmin SQL Dump
-- version 2.8.0.1
--
www.phpmyadmin.net
--
-- Host:
-- Generation Time: Apr 27, 2012 at 05:11 AM
-- Server version: 5.0.91
-- PHP Version: 4.4.9
--
-- Database: `jml_`
--
--
--
-- Table structure for table `yvbwn_hikashop_address`
--
CREATE TABLE `yvbwn_hikashop_address` (
`address_id` int( 10 ) unsigned NOT NULL AUTO_INCREMENT ,
`address_user_id` int( 10 ) unsigned NOT NULL default '0',
`address_title` varchar( 255 ) default NULL ,
`address_firstname` varchar( 255 ) default NULL ,
`address_middle_name` varchar( 255 ) default NULL ,
`address_lastname` varchar( 255 ) default NULL ,
`address_company` varchar( 255 ) default NULL ,
`address_street` varchar( 255 ) default NULL ,
`address_post_code` varchar( 255 ) default NULL ,
`address_city` varchar( 255 ) default NULL ,
`address_telephone` varchar( 255 ) default NULL ,
`address_telephone2` varchar( 255 ) default NULL ,
`address_fax` varchar( 255 ) default NULL ,
`address_state` varchar( 255 ) default NULL ,
`address_country` varchar( 255 ) default NULL ,
`address_published` tinyint( 4 ) NOT NULL default '1',
`address_vat` varchar( 255 ) default NULL ,
`address_default` tinyint( 4 ) NOT NULL default '0',
PRIMARY KEY ( `address_id` ) ,
KEY `address_user_id` ( `address_user_id` )
) ENGINE = MYISAM DEFAULT CHARSET = utf8 AUTO_INCREMENT =1;
MySQL said: Documentation
#1050 - Table 'yvbwn_hikashop_address' already exists